Dear Steve,
Thank you for your explaination. I really appreciate it. I had download the gms program and I will study the MCP and NLP portion in the User Guide .
Thanks a lot.
Regards,
Douglas
Search found 21 matches
- 3 years ago
- Forum: Syntax
- Topic: EXIT CODE =3 , the equation is infes
- Replies: 11
- Views: 8756
- 3 years ago
- Forum: Syntax
- Topic: EXIT CODE =3 , the equation is infes
- Replies: 11
- Views: 8756
Re: EXIT CODE =3 , the equation is infes
Dear Renger, My problems were solved! Thanks for all your help! I still have two questions: (1) After removing the lower bound, the problem solved. The unmatched variables disappeared. I really wondering why? It took very a lot of time. In order to avoid dividing by zero, I followed the instruction ...
- 3 years ago
- Forum: Syntax
- Topic: EXIT CODE =3 , the equation is infes
- Replies: 11
- Views: 8756
Re: EXIT CODE =3 , the equation is infes
Dear Renger,
Thank you for your patience. Fixing the variable to check the feasibility is the method in the Appendix in Horse's book.
I will study the materials you provide.
Thanks again.
Regards,
Douglas
Thank you for your patience. Fixing the variable to check the feasibility is the method in the Appendix in Horse's book.
I will study the materials you provide.
Thanks again.
Regards,
Douglas
- 3 years ago
- Forum: Syntax
- Topic: EXIT CODE =3 , the equation is infes
- Replies: 11
- Views: 8756
Re: EXIT CODE =3 , the equation is infes
Dear Renger, I am sorry to ask the same question again. Please find the file which named *1212.gms attached. In this file, I add the cge.iterlim=0 and find: ---- QINTfn =E= QINTfn(comagr,secagr).. - 0.404883820662826*QINTA(secagr) + QINT(comagr,secagr) =E= 0 ; (LHS = -14656.9114743557, INFES = 14656...
- 3 years ago
- Forum: Syntax
- Topic: EXIT CODE =3 , the equation is infes
- Replies: 11
- Views: 8756
Re: EXIT CODE =3 , the equation is infes
Dear Renger,
Thanks for the reply. I will try it. I will be very happy if I can solve the infeasible problem even though another problem will be encountered soon.
Thanks.
Douglas
Thanks for the reply. I will try it. I will be very happy if I can solve the infeasible problem even though another problem will be encountered soon.
Thanks.
Douglas
- 3 years ago
- Forum: Syntax
- Topic: EXIT CODE =3 , the equation is infes
- Replies: 11
- Views: 8756
Re: EXIT CODE =3 , the equation is infes
Dear Renger, I use the command cge.iterlim you suggested to check the Infeasible. The equation changed from no problem to Infeasible, but I think the equation is simple and shouldn't have the problem. Could you please help with thanks. (page 26, the ifpri model you mentioned, intermediate demand for...
- 3 years ago
- Forum: Syntax
- Topic: EXIT CODE =3 , the equation is infes
- Replies: 11
- Views: 8756
EXIT CODE =3 , the equation is infes
Dear all, I am working on the CGE model. I don't finish the whole model yet. Up to this stage, I have written the equations and I fix all the variables to check all the equations. I encounter two questions: (1) some equation showed "infes", but the value is very small. For example, 0.002 o...
- 3 years ago
- Forum: Syntax
- Topic: error code 57 and 52: VAR operands relational or boolean
- Replies: 1
- Views: 1470
Re: error code 57 and 52: VAR operands relational or boolean
I got some typing error!
CETZEROfn(a)$(QDA(a)=0)..
Should be QDA0(a)
- please ignore this post --
Thank you.
CETZEROfn(a)$(QDA(a)=0)..
Should be QDA0(a)
- please ignore this post --
Thank you.
- 3 years ago
- Forum: Syntax
- Topic: error code 57 and 52: VAR operands relational or boolean
- Replies: 1
- Views: 1470
error code 57 and 52: VAR operands relational or boolean
Dear All, I am struggling with my model. There is zero in my data: QDA0(a)=sum(c,sam(a,c))/PDA0(a); I use "$" to control it and got the error: 57 Thank you for your help in advance. CETfn(a)$(QDA0(a)).. QA(a)=e=scaleCET(a)*(deltaCET(a)*QDA(a)**rhoCET(a)+(1-deltaCET(a))*QE(a)**rhoCET(a))**(...
- 3 years ago
- Forum: Syntax
- Topic: Exit code = 2, Endogenous relational operations require model type "dnlp"?
- Replies: 3
- Views: 2670
Re: Exit code = 2, Endogenous relational operations require model type "dnlp"?
Dear Renger,
Thank you very much. I will try it.
Thanks and regards,
Douglas
Thank you very much. I will try it.
Thanks and regards,
Douglas