GAMS World Forum

Hi, I think that order doesn't matter when you defining an equation.

set tid /2000*2014/;

equationx(tid)$condition(tid).. "an equation"

Hi, to be able to compare them I think they should be defined as parameters.
Another possibility is to use auxiliary parameters.
To search for a string in a set, I usually use the "sameas" command.
Bye!

Hi, the problem is in set k at the end of the equation: ...V_NEG*dm(j,k)/sum(jj,dm(jj,k)); This is the equation exactly like the one in the image: eq_margen_1(j) .. sum(p,is(j,p))+ sum(i,th(j,i)*Y(i,j)) - sum(k,dm(j,k)) =G= sum(jj, sum(p,is(jj,p))+ sum(i,th(jj,i)*Y(i,jj)) - sum(k,dm(jj,k)))*V_NEG*dm...

Hi, you must specify that MM(i,k) is a binary variable.
Bye

Hi, I think this can work. Maybe it should be modified for a greater generality Bye! set i your set i /1*55/ n number of pattern /p1*p6/ j your set j /40,50,60/ pattern(n,j) pattern definition /p1.40,p2.50,p3.60,p4.40,p4.50,p5.40,p5.60,p6.50,p6.60/ ; table D(i,j) 40 50 60 1 40 50 2 60 3 40 9 50 17 5...

Hi, you must always reference to the original set (i, j) for example: set i /i1*i10/ j /j1*j15/ h /h1*h40/ technology(i,j) subset_of_tech(i,j) ; technology(i,j)= some set definition subset_of_tech(i,j)= some set definition constraint(i,j,h)$(technology(i,j) and subset_of_tech(technology)).. var(i,j,...

Hello, do you need the product of three variables? If so, you can linearizing the product of two binary variables (Quality of production and Transportation area); this generate a new binary variable (suppose QT). Finally, you can linearizing the product of a binary and a continuous variable (QT and ...

Hi, I hope this can help you.
Bye

constraint(technology)$subset_of_tech(technology).. var(technology) =g= par(technology);

Hi, you can use a bounded continuous variable.
positive variable
T
;
T.lo=50;
T.up=150;

This works, except if you need that the variable take integer values.
Bye

Hi, it's simple

set i warehouse /1*3/;
alias(i,j);

eq(i,j)$(ord(i) ne ord(j)).. X(i,i) =g= X(i,j);


Bye