how to code the position of last element in a set

[Archiver]

Hallo,

the position for the first element in a set we can code like this: ord(i)=1, how to code the position for the last one?

Thanks in advance.

Yu

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[Archiver]

hallo,

i mean the element in a set is infinity.

Thank you!> 写道：

> Hallo,
>
> the position for the first element in a set we can code like this: ord(i)=1, how to code the position for the last one?
>
> Thanks in advance.
>
> Yu
>
> --
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[Archiver]

Hi Yu

Use card(i) which will give you the cardinality of the set (the number of elements)

Cheers

Renger



From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com] On Behalf Of Yu Li
Sent: Dienstag, 19. Januar 2016 15:14
To: gamsworld
Subject: how to code the position of last element in a set



Hallo,



the position for the first element in a set we can code like this: ord(i)=1, how to code the position for the last one?



Thanks in advance.



Yu

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[Archiver]

hi Renger,

I want to defind the order of the element. I show you my example:

my code:

NB5(i,l)$(ord(l)>1 and ord(l)1 and ord(l) 写道：

> Hi Yu
> Use card(i) which will give you the cardinality of the set (the number of elements)
> Cheers
> Renger
>
> From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com] On Behalf Of Yu Li
> Sent: Dienstag, 19. Januar 2016 15:14
> To: gamsworld
> Subject: how to code the position of last element in a set
>
> Hallo,
>
> the position for the first element in a set we can code like this: ord(i)=1, how to code the position for the last one?
>
> Thanks in advance.
>
> Yu
> --
> To unsubscribe from this group and stop receiving emails from it, send an email to gamsworld+unsubscribe@googlegroups.com.
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[Archiver]

NB5(i,l)$(ord(l)>1 and ord(i) 1 and ord(l)1 and ord(l) 写道：



Hi Yu

Use card(i) which will give you the cardinality of the set (the number of elements)

Cheers

Renger



From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com] On Behalf Of Yu Li
Sent: Dienstag, 19. Januar 2016 15:14
To: gamsworld
Subject: how to code the position of last element in a set



Hallo,



the position for the first element in a set we can code like this: ord(i)=1, how to code the position for the last one?



Thanks in advance.



Yu

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[Archiver]

hi Renger,

thank you for you help, but i don’t unterstand , why hier is ord(i) 写道：

> NB5(i,l)$(ord(l)>1 and ord(i) Cheers
> Renger
>
> From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com]
> Sent: Dienstag, 19. Januar 2016 16:15
> To: gamsworld@googlegroups.com
> Subject: Re: how to code the position of last element in a set
>
> hi Renger,
>
> I want to defind the order of the element. I show you my example:
>
>
> my code:
>
> NB5(i,l)$(ord(l)>1 and ord(l) NB6(i,l)$(ord(l)>1 and ord(l)
> In there 1 ist the number of order for the first element, is the order number for the last one.
>
> some advice. Thank you!
>
> Best regards
>
> Yu
> 在 2016年1月19日，15:58，Renger van Nieuwkoop 写道：
>
>
> Hi Yu
> Use card(i) which will give you the cardinality of the set (the number of elements)
> Cheers
> Renger
>
> From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com] On Behalf Of Yu Li
> Sent: Dienstag, 19. Januar 2016 15:14
> To: gamsworld
> Subject: how to code the position of last element in a set
>
> Hallo,
>
> the position for the first element in a set we can code like this: ord(i)=1, how to code the position for the last one?
>
> Thanks in advance.
>
> Yu
> --
> To unsubscribe from this group and stop receiving emails from it, send an email to gamsworld+unsubscribe@googlegroups.com.
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>
>
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[Archiver]

Yes, it should be.

Cheers

Renger



From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com]
Sent: Mittwoch, 20. Januar 2016 09:49
To: gamsworld@googlegroups.com
Subject: Re: how to code the position of last element in a set



hi Renger,



thank you for you help, but i don’t unterstand , why hier is ord(i) 写道：



NB5(i,l)$(ord(l)>1 and ord(i)



my code:



NB5(i,l)$(ord(l)>1 and ord(l)1 and ord(l) is the order number for the last one.



some advice. Thank you!



Best regards



Yu

在 2016年1月19日，15:58，Renger van Nieuwkoop 写道：




Hi Yu

Use card(i) which will give you the cardinality of the set (the number of elements)

Cheers

Renger



From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com] On Behalf Of Yu Li
Sent: Dienstag, 19. Januar 2016 15:14
To: gamsworld
Subject: how to code the position of last element in a set



Hallo,



the position for the first element in a set we can code like this: ord(i)=1, how to code the position for the last one?



Thanks in advance.



Yu

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[Archiver]

hi Renger,

thank you very much again!

Yu
在 2016年1月20日，10:56，Renger van Nieuwkoop 写道：

> Yes, it should be.
> Cheers
> Renger
>
> From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com]
> Sent: Mittwoch, 20. Januar 2016 09:49
> To: gamsworld@googlegroups.com
> Subject: Re: how to code the position of last element in a set
>
> hi Renger,
>
> thank you for you help, but i don’t unterstand , why hier is ord(i)
> Best regards
>
> Yu
> 在 2016年1月19日，16:25，Renger van Nieuwkoop 写道：
>
>
> NB5(i,l)$(ord(l)>1 and ord(i) Cheers
> Renger
>
> From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com]
> Sent: Dienstag, 19. Januar 2016 16:15
> To: gamsworld@googlegroups.com
> Subject: Re: how to code the position of last element in a set
>
> hi Renger,
>
> I want to defind the order of the element. I show you my example:
>
>
> my code:
>
> NB5(i,l)$(ord(l)>1 and ord(l) NB6(i,l)$(ord(l)>1 and ord(l)
> In there 1 ist the number of order for the first element, is the order number for the last one.
>
> some advice. Thank you!
>
> Best regards
>
> Yu
> 在 2016年1月19日，15:58，Renger van Nieuwkoop 写道：
>
>
>
> Hi Yu
> Use card(i) which will give you the cardinality of the set (the number of elements)
> Cheers
> Renger
>
> From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com] On Behalf Of Yu Li
> Sent: Dienstag, 19. Januar 2016 15:14
> To: gamsworld
> Subject: how to code the position of last element in a set
>
> Hallo,
>
> the position for the first element in a set we can code like this: ord(i)=1, how to code the position for the last one?
>
> Thanks in advance.
>
> Yu
> --
> To unsubscribe from this group and stop receiving emails from it, send an email to gamsworld+unsubscribe@googlegroups.com.
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>
> --
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>
>
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[Archiver]

hi Renger,

can you please help me again, how can i write the code for output the number of Iteration for some certain model, is there an option for this or some easy way?

Thank you!

yu
在 2016年1月20日，10:56，Renger van Nieuwkoop 写道：

> Yes, it should be.
> Cheers
> Renger
>
> From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com]
> Sent: Mittwoch, 20. Januar 2016 09:49
> To: gamsworld@googlegroups.com
> Subject: Re: how to code the position of last element in a set
>
> hi Renger,
>
> thank you for you help, but i don’t unterstand , why hier is ord(i)
> Best regards
>
> Yu
> 在 2016年1月19日，16:25，Renger van Nieuwkoop 写道：
>
>
> NB5(i,l)$(ord(l)>1 and ord(i) Cheers
> Renger
>
> From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com]
> Sent: Dienstag, 19. Januar 2016 16:15
> To: gamsworld@googlegroups.com
> Subject: Re: how to code the position of last element in a set
>
> hi Renger,
>
> I want to defind the order of the element. I show you my example:
>
>
> my code:
>
> NB5(i,l)$(ord(l)>1 and ord(l) NB6(i,l)$(ord(l)>1 and ord(l)
> In there 1 ist the number of order for the first element, is the order number for the last one.
>
> some advice. Thank you!
>
> Best regards
>
> Yu
> 在 2016年1月19日，15:58，Renger van Nieuwkoop 写道：
>
>
>
> Hi Yu
> Use card(i) which will give you the cardinality of the set (the number of elements)
> Cheers
> Renger
>
> From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com] On Behalf Of Yu Li
> Sent: Dienstag, 19. Januar 2016 15:14
> To: gamsworld
> Subject: how to code the position of last element in a set
>
> Hallo,
>
> the position for the first element in a set we can code like this: ord(i)=1, how to code the position for the last one?
>
> Thanks in advance.
>
> Yu
> --
> To unsubscribe from this group and stop receiving emails from it, send an email to gamsworld+unsubscribe@googlegroups.com.
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>
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>
>
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[Archiver]

Hi Yu



You can the iterations used to solve a model by storing yourmodelname.iterusd in a parameter.



e.g.

model test /all/;

solve test…

parameter iterationsused;

iterationsused = test.iterusd;

Cheers



Renger



From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com]
Sent: Freitag, 22. Januar 2016 18:59
To: gamsworld@googlegroups.com
Subject: Re: how to code the position of last element in a set



hi Renger,



can you please help me again, how can i write the code for output the number of Iteration for some certain model, is there an option for this or some easy way?



Thank you!



yu

在 2016年1月20日，10:56，Renger van Nieuwkoop 写道：



Yes, it should be.

Cheers

Renger



From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com]
Sent: Mittwoch, 20. Januar 2016 09:49
To: gamsworld@googlegroups.com
Subject: Re: how to code the position of last element in a set



hi Renger,



thank you for you help, but i don’t unterstand , why hier is ord(i) 写道：




NB5(i,l)$(ord(l)>1 and ord(i)



my code:



NB5(i,l)$(ord(l)>1 and ord(l)1 and ord(l) is the order number for the last one.



some advice. Thank you!



Best regards



Yu

在 2016年1月19日，15:58，Renger van Nieuwkoop 写道：





Hi Yu

Use card(i) which will give you the cardinality of the set (the number of elements)

Cheers

Renger



From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com] On Behalf Of Yu Li
Sent: Dienstag, 19. Januar 2016 15:14
To: gamsworld
Subject: how to code the position of last element in a set



Hallo,



the position for the first element in a set we can code like this: ord(i)=1, how to code the position for the last one?



Thanks in advance.



Yu

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