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I want to define three equations for three-time steps.

For the first hour, I can write the following:

p(s,h) $(ord(h) eq 1)..

The last hour will be the following:

p(s,h) $(ord(h) eq card(h))..

I am trying to write equations for the hours in between something like this but can't get the syntax right.

p(s,h) $(ord(h) gt 1 & ord(h) lt card(h))..

I would appreciate any help on this.

Hi
Yould define a parameter as follows: Cheers
Renger

Suppose that you are hired as a decision maker for a charity organization called "Help!". This year the
organisation is planning to distribute support packages including basic needs (bottles of water, bread, canned
food etc.) to people in need in their neighbourhood. Some volunteers collected data from around and found
that there are 24 houses which are suitable for this support and gave you the coordinates for those houses.

Houses 1 2 3 4 5 6 7 8 9 10 11 12
x 6 14 14 4 3 10 20 7 12 5 16 6
y 19 7 4 6 13 12 8 17 12 11 19 6
Houses 13 14 15 16 17 18 19 20 21 22 23 24
x 11 14 18 20 11 3 3 6 17 6 17 5
y 16 16 8 12 2 2 11 16 19 3 12 10
Table 1: Coordinates of the houses.
According to the given information try to make decisions for the following problems

Could you help me please have a healtyh days

Renger wrote: ↑4 years ago Hi
Yould define a parameter as follows:

Code: Select all

alias(h,ah);

parameter hnr(h)  Hour ord;

hnr(h) = ord(h);

p(s,h,ah)$(ord(h) eq hnr(h))..

Cheers
Renger

I tried the proposed way but I think I didn't quite understand the way you proposed to solve this. Let's say, How do I write the code using the method you suggested for hours 2 to 9. I really appreciate your help on this.

Hi

Sorry, my mistake. Here a solution: you split the equation in three parts and use the conditions on those parts THis will result in A(s,h) begin 12 in the first hour, 10 in the in-between hours, and 8 in the last hour.
I hope this helps
Cheers
Renger