Assign previous iteration result to starting value of next iteration Topic is solved

[bigakrim]

Good morning everyone
I am optimizing an iterative process and I have to assign a certain variable result as the fixed value of that variable for the next iteration optimization.
I wonder how to code this. I tried to code it but when I run the model, from the listing file it seems that Gams assigns 'zero' as the fixed value
of the variable for the next iteration.
Please help me

opt_rolling.gms

(8.28 KiB) Downloaded 224 times

inputdata.xlsx

(19.69 KiB) Downloaded 224 times

[Fred]

Hi,

You can see in the column listing column listing that R(s1) and Q(s1) are fixed to 4 for the first iteration which seems to be intended. For subsequent iterations you do

Code: Select all

if (ord(it)>1,
R.fx(s)$(ord(s)=1)=R.l(s)$(ord(s)=ch and ord(it)=ord(it)-1);
Q.fx(s)$(ord(s)=1)=Q.l(s)$(ord(s)=ch and ord(it)=ord(it)-1);
);

This basically means

Code: Select all

R.fx('s1') = 0;
Q.fx('s1') = 0;

The dollar condition on the left hand side restricts the assignment to s1. The dollar condition on the right hand side always evaluates to false:
- ord(s)=ch is false because s is controlled on the LHS already where you restrict the assignment to ord(s)=1. But ch is equal to 3
- ord(it)=ord(it)-1 is never true (I think this is obvious).

I hope this helps!

Fred

[bigakrim]

thanks, Ms. Fred for your answer and code explanation.
How should I code if I want gams to assign the result R.l (s=3, it=1) as fixed value R.fx(s=1, it=2) for iteration it=2
and R.l(s=3, it=2) for R.fx(s=1, it=3)
and finally for the last iteration R.l(s=3, it=3) for R.fx(s=1, it=4)
thanks to help me.

[Fred]

If I understand correctly what you try to do, you could just write

Code: Select all

[...]
if(ord(it)=1,
  R.fx('s1')=4;
  Q.fx('s1')=4;
else
  R.fx('s1') = R.l('s3');
  Q.fx('s1') = R.l('s3');
);

Solve rolling using LP minimizing cost;
[...]

I hope this helps!

Fred